4[b-(3-b)]=6(b+4)

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Solution for 4[b-(3-b)]=6(b+4) equation:


Simplifying
4[b + -1(3 + -1b)] = 6(b + 4)
4[b + (3 * -1 + -1b * -1)] = 6(b + 4)
4[b + (-3 + 1b)] = 6(b + 4)

Reorder the terms:
4[-3 + b + 1b] = 6(b + 4)

Combine like terms: b + 1b = 2b
4[-3 + 2b] = 6(b + 4)
[-3 * 4 + 2b * 4] = 6(b + 4)
[-12 + 8b] = 6(b + 4)

Reorder the terms:
-12 + 8b = 6(4 + b)
-12 + 8b = (4 * 6 + b * 6)
-12 + 8b = (24 + 6b)

Solving
-12 + 8b = 24 + 6b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6b' to each side of the equation.
-12 + 8b + -6b = 24 + 6b + -6b

Combine like terms: 8b + -6b = 2b
-12 + 2b = 24 + 6b + -6b

Combine like terms: 6b + -6b = 0
-12 + 2b = 24 + 0
-12 + 2b = 24

Add '12' to each side of the equation.
-12 + 12 + 2b = 24 + 12

Combine like terms: -12 + 12 = 0
0 + 2b = 24 + 12
2b = 24 + 12

Combine like terms: 24 + 12 = 36
2b = 36

Divide each side by '2'.
b = 18

Simplifying
b = 18

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